0=15y^2-2y-1

Solution for 0=15y^2-2y-1 equation:

0=15y^2-2y-1

We move all terms to the left:

0-(15y^2-2y-1)=0

We add all the numbers together, and all the variables

-(15y^2-2y-1)=0

We get rid of parentheses

-15y^2+2y+1=0

a = -15; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-15)·1
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8}{2*-15}=\frac{-10}{-30}
=1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8}{2*-15}=\frac{6}{-30}
=-1/5
$